Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.

Find the distance BB'

Answer 1

@jim_thompson5910

Answer 2

@mvrc1996 are you there? still need help?

Answer 3

yes:D but on a different one now

Answer 4

Find the distance CC'

Answer 5

what i got to was sqrt29 but thats not it

Answer 6

if you know how to find BB' just do the same with CC'

Answer 7

ok, tell me how to find C' by the transformation T?

Answer 8

(3+2)^2+ (0-2)^2

Answer 9

5^2+(-2)^2

Answer 10

25+4

Answer 11

sqrt29

Answer 12

why do you square them? the transformation T tells us that x---> x+2 and y ---> y+1 only, not square

Answer 13

because when using the distance formula which is what you se to find them you square them

Answer 14

and the way the answer tells me to do it its squared idk how to explain that to you

Answer 15

oh no!! you first find out the coordinate of C' , from C ( -2 ,2) you have C' (0, 3) , right?

Answer 16

yes

Answer 17

and then from that, apply the distance formula to find the length of CC'

Answer 18

ik its squared because it has a sqrt and then im suppost to put the numbers in

Answer 19

thats exactly the process i showed you up above

Answer 20

oh wait i had 2,-2 not -2,2

Answer 21

for what? C, C'?

Answer 22

yes

Answer 23

is the answer sqrt5 i think it is

Answer 24

?

Answer 25

at the end up, you have c( -2,2) and C'( 0,3) right?

Answer 26

yes

Answer 27

the distance formula give you
that's it