PLEASE HELP! can someone help me put
x=3y and x=y^2+6y into a y-intercept form so I could figure our the intercept of the two equation on my graph

Question

PLEASE HELP! can someone help me put 
x=3y and x=y^2+6y into a y-intercept form so I could figure our the intercept of the two equation on my graph

anonymous · Answer

x=3y
Divide by 3 on both sides.
1/3x=y
Flip if you want to
y=1/3x

anonymous · Answer

I don't know about the other one though.

anonymous · Answer

yes that where I am stuck on.

anonymous · Answer

try to have perfect square by add 9 in both sides, you have x + 9 = y^2 +6y +9 = (y+3)^2 . then take square root both side, you have y + 3 = sqrt ( x+9) then subtract both sides by 3 you have y = sqrt ( x +9) -3 that's the form you need

anonymous · Answer

got it?

anonymous · Answer

yes i but it wont show the interception on my graph my i eyeballed it thanks.