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Mathematics 19 Online
OpenStudy (christos):

http://screencast.com/t/OJsN9PMfDMk Can you help me solve this?

OpenStudy (oaktree):

As x approaches negative infinity, y approaches 2. As x approaches positive infinity, y approaches 0.

OpenStudy (christos):

Why not : As x approaches negative infinity, y approaches -2. As x approaches negative infinity, y approaches 2.

OpenStudy (christos):

I took the other line the one below the other

OpenStudy (oaktree):

No, because if you look at the left hand of the graph, (where x approaches negative infinity) the graph is tending towards y=2. Similarly, on the right hand side, (where x approaches positive infinity) the graph tends toward y=0.

OpenStudy (christos):

so why the one that tends toward 0 is correct and the one that tends toward 2 is wrong

OpenStudy (oaktree):

Pardon? What do you mean?

OpenStudy (christos):

" (where x approaches negative infinity) the graph is tending towards y=2. Similarly, on the right hand side, (where x approaches positive infinity) the graph tends toward y=0." I don't understand why your explanation above makes it wrong

OpenStudy (christos):

Do you understand me now?

OpenStudy (christos):

@OakTree

OpenStudy (oaktree):

Makes what wrong?

OpenStudy (christos):

This: "Why not : As x approaches negative infinity, y approaches -2. As x approaches negative infinity, y approaches 2."

OpenStudy (oaktree):

Because you have two statements for negative infinity. The graph can only asymptote to a single line.

OpenStudy (christos):

Sorry if I sound stupid but, What do you mean by "asymptote" ? :S

OpenStudy (oaktree):

To tend to a value. So the graph kind of looks like it's going to almost touch 0 but not quite? That's called asymptoting.

OpenStudy (christos):

but the first line has 2 asymptotes as well, one end tends to 2 other end tends to 0

OpenStudy (oaktree):

Right. That's why I said that as x approaches negative infinity, the value is 2, and on the other end it's 0. Look at my first response to your question.

OpenStudy (christos):

But that's because you took into consideration the first line

OpenStudy (oaktree):

What line are you talking about?

OpenStudy (christos):

What if I take the second line and say: when x-> - infinity y is 2 and when x-- > -infinity from the other end of the line then y is -2 and I am talking about this line http://screencast.com/t/izH8AutVI62

OpenStudy (christos):

@OakTree

OpenStudy (anonymous):

both lines together make up the function

OpenStudy (anonymous):

and the question asks about the function

OpenStudy (e.mccormick):

You need to look at what x going to \(-\infty\). It seems you are looking at the y value, not the x.

OpenStudy (e.mccormick):

that x, not what x. Or the x...

OpenStudy (anonymous):

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OpenStudy (e.mccormick):

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