Been struggling with this for an hour -_- write an equation for the translation of y=3/x that has the asymptotes x=-6 and y=7
an hour?
you want an asymptote of \(x=-6\) make sure \(-6\) is a zero of the denominator
i.e. make the denominator \(x+6\)
Unfortunately. :/ it's embarrassing. I finished everything else on this silly packet with minimal problems. This is giving me a ton of trouble for some reason.
oh i forgot the part about \(y=7\) make sure to put \(7y\) in the numerator
you can use \[\frac{7x}{x+6}\] or if you need that 3 up top put \[\frac{7x+3}{x+6}\]
i meant put \(7x\) in the numerator, not \(7y\)
sorry i haven't been replying. i typed something out but this website wasn't responding to my phone very well but im on the computer now. here's what confuses me: if i need the horizontal and vertical asymptote added to the equation, the vertical asymptote is y=7 right? so if i'm thinking about working backwards i would need the denominator to be x-7 to get 7 when it's set equal to zero right? or am i completely off so far?
when i type 3/(x-7) into my calculator it seems right for the first asymptote so now i guess i'm just lost with the second one
no i think you have it backwards
if \(y=7\) us a horizontal asymptote then a) the degree of the top has to equal the degree of the bottom and b) the ratio of the leading coefficients has to be 7
also \(y=7\) is a HORIZONTAL line, i.e a horizontal asymptote, not a vertical one
Wow. I feel horribly stupid. That would explain why I'm having issues.
Okay your answer makes a lot more sense now that I'm not mixed up. Thanks for your help. You have a nice night. :)
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