Factor completely: 9x2 + 42x + 49 (3x + 7)(3x − 7) (9x − 7)(9x − 7) (3x + 7)(3x + 7) (9x + 7)(9x + 7) Please help it's 11:50 and my head is about to explode D:
Well at first sight, can't you right away eliminate B & D?
Do you know why?
I would, 3 hours ago but now no :(
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hmm, okay making some sense.
Samw goes with choice D. Since there are 9x and 9x; thus when you multiply them, you get 81x^2 not 9x^2 which is what you want. Therefore: you want (3x + ?)(3x+?) or (3x + ?)(3x - ?)
*same
That leaves us to work with choice A & C
Ok, iv'e been trying to make sense of how to do this but I can't think straight, if it were an x2 + x + x it would be much easier
But are you understand better now? :)
yes it makes the question easier knowing I only have to distinguish one sign + or - :D
Okaii well lets continue then :)
alrighty
BTW do you know how to FOIL?
I know the basic yes
\[9x^2 + 42x + 49\] So you need something like this: Choice 1: (3x + ?) (3x + ?) or Choice 2: (3x + ?) (3x - ?) ----------------------------- Now you need to find a number that when multiplied equals +49
1*49 and 7*7 is all I can think of
Okaii good good :) so +7 and +7 is in one the choices =, right? So it would be : (3x + 7)(3x + 7) We can double check by FOIL (3x + 7)(3x + 7) can also be written as (3x + 7)^2
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I have to be seriously fried to not have realized this >_<
Thank you so much you have no idea how much you helped me :D
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