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Mathematics 16 Online
OpenStudy (ja1):

Factor completely: 9x2 + 42x + 49 (3x + 7)(3x − 7) (9x − 7)(9x − 7) (3x + 7)(3x + 7) (9x + 7)(9x + 7) Please help it's 11:50 and my head is about to explode D:

OpenStudy (anonymous):

Well at first sight, can't you right away eliminate B & D?

OpenStudy (anonymous):

Do you know why?

OpenStudy (ja1):

I would, 3 hours ago but now no :(

OpenStudy (anonymous):

|dw:1367812393687:dw|

OpenStudy (ja1):

hmm, okay making some sense.

OpenStudy (anonymous):

Samw goes with choice D. Since there are 9x and 9x; thus when you multiply them, you get 81x^2 not 9x^2 which is what you want. Therefore: you want (3x + ?)(3x+?) or (3x + ?)(3x - ?)

OpenStudy (anonymous):

*same

OpenStudy (anonymous):

That leaves us to work with choice A & C

OpenStudy (ja1):

Ok, iv'e been trying to make sense of how to do this but I can't think straight, if it were an x2 + x + x it would be much easier

OpenStudy (anonymous):

But are you understand better now? :)

OpenStudy (ja1):

yes it makes the question easier knowing I only have to distinguish one sign + or - :D

OpenStudy (anonymous):

Okaii well lets continue then :)

OpenStudy (ja1):

alrighty

OpenStudy (anonymous):

BTW do you know how to FOIL?

OpenStudy (ja1):

I know the basic yes

OpenStudy (anonymous):

\[9x^2 + 42x + 49\] So you need something like this: Choice 1: (3x + ?) (3x + ?) or Choice 2: (3x + ?) (3x - ?) ----------------------------- Now you need to find a number that when multiplied equals +49

OpenStudy (ja1):

1*49 and 7*7 is all I can think of

OpenStudy (anonymous):

Okaii good good :) so +7 and +7 is in one the choices =, right? So it would be : (3x + 7)(3x + 7) We can double check by FOIL (3x + 7)(3x + 7) can also be written as (3x + 7)^2

OpenStudy (anonymous):

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OpenStudy (ja1):

I have to be seriously fried to not have realized this >_<

OpenStudy (ja1):

Thank you so much you have no idea how much you helped me :D

OpenStudy (anonymous):

|dw:1367813705268:dw|

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