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Mathematics 8 Online
OpenStudy (anonymous):

Calculus EXPERTS help, pretty please The rate of fuel consumption is increasing the fastest at time t = 22.5. What is the value of R''(22.5)? Explain your reasoning.

OpenStudy (anonymous):

OpenStudy (anonymous):

okay I realize 22.5 is in between 15 and 30 , but i have no idea how to go about finding the double prime? Please help me, Thank you so much!

OpenStudy (fibonaccichick666):

So when you graph the curve, what would you have around 22.5?

OpenStudy (anonymous):

looks like 45

OpenStudy (anonymous):

so that's R(22.5)

OpenStudy (fibonaccichick666):

not quite, I mean does it look like a hill or a valley

OpenStudy (fibonaccichick666):

think about what it looks like not the actual pts

OpenStudy (anonymous):

OpenStudy (anonymous):

made this in excel. I can see the derivative would be increasing at this point

OpenStudy (fibonaccichick666):

ooh goody, You're thinking on the right track, but the derivative would just be positive

OpenStudy (fibonaccichick666):

now can you tell me what the derivative at the highest spot on that graph you showed me is?

OpenStudy (anonymous):

when t=50 the derivative is 0

OpenStudy (fibonaccichick666):

good and why?

OpenStudy (anonymous):

because there is no slope, how about at 22.5 ?

OpenStudy (fibonaccichick666):

not the reason, what happens at t=50?

OpenStudy (fibonaccichick666):

It is a ____________.

OpenStudy (anonymous):

Well, the rate at which the fuel is consumed stops, begins to decrease

OpenStudy (anonymous):

maximum

OpenStudy (fibonaccichick666):

right,

OpenStudy (fibonaccichick666):

yes!

OpenStudy (anonymous):

oh, so at R"(22.5) it would also be 0? :)

OpenStudy (fibonaccichick666):

yes can you tell me why?

OpenStudy (anonymous):

because this is the maximum of the derivative of R(t). Fastest rate of consumption

OpenStudy (fibonaccichick666):

yep! And the derivative (in this case)tells us that we have either a max or a min then its derivative =0

OpenStudy (anonymous):

Thanks, you helped me think this one through! Medal :)

OpenStudy (fibonaccichick666):

np good luck with calc!

OpenStudy (anonymous):

Thanks!

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