The average surface pressure on Mars is 0.80 kPa and the acceleration of gravity is only 3.7 m/s2. With a barometer on Mars, what is the height of the column of mercury, assuming that mercury is liquid with a density of 13.6 × 103 kg/m3?
Do you remember\[P=\rho g h\]?
I'm not sure, about unit
Pressure will be in pascals \[800=(13.6)(3.7)(h) \\ \\ h=\frac{800}{13.6 \times 3.7}\]
\[800=(13.6)(3.7)(h) \\ \\ h=\frac{800}{(13.6\times 10^3) \times 3.7} \huge ^{*}\]
Ok thank u so much
We don't care about unit?
The answers is 16mm
Yeah
The units cancels out giving meters, which is height.
Is 16mm the actual answer or that's what you found out?
Nope, that is my teacher answer
ok we got that
\[800Pa=(13.6\times 10^{3}kgm^{-3})(3.73.7ms^{-2})(h)\] Pascal has units \(\Large kgm^{-1}s^{-1}\) \[h=\frac{800kgm^{-1}s^{-1}}{(13.6\times 10^3kgm^{-3}) \times 3.7ms^{-2}}\] \[h=0.0159m=0.016m=16mm\]
Thanks
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