Question

Rewrite the expression
ln(a+b)+5ln(a−b)−4ln c
as a single logarithm lnA. Then the function
A=

Answer 1

so what properties do you know about logs?

Answer 2

would it be that ln(ab)=ln(a+b)
and that ln(a/b)=ln(a-b)

Answer 3

that's the tricky part. what you said is not correct.

ln(a) + ln(b) = ln(ab)

Answer 4

i have the answer ready to paste whenever you want it. let me know when you're done attempting ^_^

Answer 5

also remember that you have another property that deals with exponents and I agree with @Euler271 's correction.

Answer 6

oh ok im not sure if its correct but i got ln(ab)+ln(a/b)^5-ln(c)^4 is that how you do it

Answer 7

take @Euler271 's coorection and use that property instead of the one you typed because it is incorrect .

Answer 8

ill paste my answer. let me know if you want me to clarify any part of it:

the answer i get is: \[\ln \frac{ (a+b)(a-b)^{5} }{ c^{4} }\]

Answer 9

^this is correct^

Answer 10

you did do the exponents correctly though :)

Answer 11

i should have put brackets around whole thing: \[\ln (\frac{ (a+b)(a-b)^{5} }{ c^{4} })\]

Answer 12

haha yes you should have. 10 pts from Ravenclaw lol

Answer 13

oh ok i think i understand