http://oi42.tinypic.com/2zgdjs0.jpg How would I solve this? I tried to multiply the (x+23) and the (x+8) and then set that to exponential form but then I got some weird answer that I'm sure is wrong.

Question

anonymous · Answer

you seem to have been on the right track.

it simplifies to: $$\log_{4} ((x+23)(x+8))$$

anonymous · Answer

which simplifies to: log_{4} (x^2 + 31x + 184) = 2

anonymous · Answer

to get rid of the log4(x) you do the inverse operation which is 4^[x]

so x^2 + 31x +184 = 4^2

anonymous · Answer

I got stuck when I got to $$x^2+31x=-168$$

anonymous · Answer

x=-7 or -24

anonymous · Answer

$$\log_{4} (x+23)(x+8)=\log_{4} 16$$

simplifies to 

$$x ^{2}+31x+168$$

which simplifies to
 
$$(x+7)(x+24)$$

anonymous · Answer

Thanks :)