3 -2 0 how do i find adjoint of the matrix? 1 4 0 0 0 2
it is the matrix of determinants obtained by using 1 point. point (1,1) = 3. eliminate the 1st row and 1st colum and take the determinant of what remains. determinant = 8. the (1,1) entry of the adjoint matrix is 8 point (2,3) = 0. eliminate 2nd row and 3rd column. take det of 3 -2 0 0 adjoint entry (2,3) = 0 hope this makes sense. if not: http://www.mathwords.com/a/adjoint.htm
kind of thank you for the input.
Matrix of minors to cofactors then transpose to adjoint.... if you can remember that Adjoint is the Transpose of Cofactor, you can usually find it. But a lot of classes do not stress it much, relying on the \(\mathrm{[A|I]}\rightarrow\mathrm{[I|A^{-1}]}\) method.
thank you
np. Have fun!
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