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Mathematics 17 Online
OpenStudy (anonymous):

a box with a square base and open top must have a volume of 32000 cm^3. find the dimensions of the box that minimize the amount of material used

OpenStudy (fibonaccichick666):

fyi I like your name. 2 how shall we approach this? any ideas?

OpenStudy (anonymous):

This is a basic optimization problem using calculus. The volume = l*w*h The surface area is what we're trying to minimize, and it equals h*w*2+h*l*2 + l*w (taking l*w=the bottom, the top does not exist)

OpenStudy (anonymous):

thanks. I'm trying to figure out how to go about it but I'm struggling with where to begin.

OpenStudy (anonymous):

There are your two functions. Oops! Square base... OK, that simplifies things.\[ Volume =x ^{2} y\] where x is the side length on the base and\[ area= x ^{2} + 4 xy\] Set volume equal to 32000, solve for x, replace y with x in your equation, and minimize.

OpenStudy (anonymous):

Nice. Thanks for the info. I'll give it a shot and I'll report back with my findings.

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