a box with a square base and open top must have a volume of 32000 cm^3. find the dimensions of the box that minimize the amount of material used
fyi I like your name. 2 how shall we approach this? any ideas?
This is a basic optimization problem using calculus. The volume = l*w*h The surface area is what we're trying to minimize, and it equals h*w*2+h*l*2 + l*w (taking l*w=the bottom, the top does not exist)
thanks. I'm trying to figure out how to go about it but I'm struggling with where to begin.
There are your two functions. Oops! Square base... OK, that simplifies things.\[ Volume =x ^{2} y\] where x is the side length on the base and\[ area= x ^{2} + 4 xy\] Set volume equal to 32000, solve for x, replace y with x in your equation, and minimize.
Nice. Thanks for the info. I'll give it a shot and I'll report back with my findings.
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