Question

xdx/(e^(3x)^2+4)

Answer 1

is it
\[e^{(3x)^2}+4\]

Answer 2

kind of lost
are you looking for the derivative?

Answer 3

got it!

you want \(u=3x^2, du=6xdx\)

Answer 4

i meant \(u=3x^2+4\)

Answer 5

then you get
\[\frac{1}{6}\int \frac{du}{e^u}\]

Answer 6

you good from there?

Answer 7

\[\frac{1}{6}\int e^{-u}du=-\frac{1}{6}e^{-u}\] and then
\[-\frac{1}{6}e^{-3x^2-4}\] or
\[\frac{1}{6e^{3x^2+4}}\]

Answer 8

Thank you. I think I begin to understand.