Question

Determine the wavelength of a 0.226 MeV photon that is emitted during gamma decay,take planks constant h=6.63*10^-23,speed of light 10^8, 1eV=1.6*10^-19.

Answer 1

\[E=hf=h \frac{ c }{ \lambda }\]
E=Energy of the photon
h=planck's constant
f=frequency
c=speed of light
\[\lambda =wavelength\]

Answer 2

since you were given 'c' )speed of light and told to find the wavelength of the photon,use
\[E=h \frac{ c }{ \lambda }\]
plug in the values you have been given and find the wavelength...

Answer 3

what do you get as your final answer??