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What is the volume of a 24.7 mol gas sample that has a pressure of .999 atm at 305 K? A:619 mL B:.691 L C:619 L
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Are you familiar with the ideal gass law? PV = nRT
NO...
HELP :(
P = pressure (in atm) V = Volume (in Liters) n = number of moles R = a constant (0.08206) T = Temperature (K) You can rewrite the equation to \[V=\frac{ nRT }{ P}\] So \[V=\frac{ 24.7*0.08206*305 }{ 0.999 }\]
OH YEA I REMEMBER THAT :) LOL
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I THINK ITS A IS THAT RIGHT?
?
if you calculate V, the answer will be in liters. (24.7*0.08206*305)/0.999 = 618.8 LITER So the answer would be C
OH TRUE I DIDNT DO THAT BUT THANK YOU SO MUCH :)
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