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Chemistry 7 Online
OpenStudy (anonymous):

What is the volume of a 24.7 mol gas sample that has a pressure of .999 atm at 305 K? A:619 mL B:.691 L C:619 L

thomaster (thomaster):

Are you familiar with the ideal gass law? PV = nRT

OpenStudy (anonymous):

NO...

OpenStudy (anonymous):

HELP :(

thomaster (thomaster):

P = pressure (in atm) V = Volume (in Liters) n = number of moles R = a constant (0.08206) T = Temperature (K) You can rewrite the equation to \[V=\frac{ nRT }{ P}\] So \[V=\frac{ 24.7*0.08206*305 }{ 0.999 }\]

OpenStudy (anonymous):

OH YEA I REMEMBER THAT :) LOL

OpenStudy (anonymous):

I THINK ITS A IS THAT RIGHT?

OpenStudy (anonymous):

?

thomaster (thomaster):

if you calculate V, the answer will be in liters. (24.7*0.08206*305)/0.999 = 618.8 LITER So the answer would be C

OpenStudy (anonymous):

OH TRUE I DIDNT DO THAT BUT THANK YOU SO MUCH :)

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