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Find the zeros of the polynomial function. f(x) = x3 + 5x2 - 4x - 20 A. x = -5, x = 4 B. x = -2, x = 2 C. x = -5, x = -2, x = 2 D. x = 5, x = -2, x = 2
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Factor by grouping: \[x^3+5x^2-4x-20=0\\ x^2(x+5)-4(x+5)=0\\ (x^2-4)(x+5)=0\]
ok cool so whats next
Do you know how to solve this? If you keep factoring, you get \[(x+2)(x-2)(x+5)=0\] From here, you split up into three equations and solve for x: \[\begin{matrix}x+2=0,&x-2=0,&x+5=0\end{matrix}\]
is it C @SithsAndGiggles
Yes
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wow thanks i think that deserves a medal lol @SithsAndGiggles
You're welcome
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