Help!! (3d²+2d-29) ÷ (d+3) Can you show me how to simlifly this by canceling like factors?
Factor the expression on the left and factor the expression on the right. Then cancel like factors.
Can the right be factored?
the right cannot be factored
IF the left side factors into something useful; it will have to be of the form: (d+3)(md + n)
if we "foil" this out ... what would you say would be a smart value for m?
@amistre64 Idk I tryed factoring it but 29 is prime with no like factors, and i still dont get how 2 foil.
f1 l1 f2 l2 (d+3) (md + n) foil is a memory method for remembering how to keep track of what you are distributing thru. F = f1 f2 = md^2 O = f1 l2 = nd I = l1 f2 = 3md L = l1 l2 = 3n equating these to what we have md^2 = 3d^2 ; m=3 (n + 3m)d = 2d 3n = -29 ; n = -29/3 (-29/3 + 3(3))d = 2d ((-29+27)/3)d = 2d (-2/3)d = 2d is rather impossiible you sure you need to factor and cancel?
All my teacher said 2 do was multiply or divide...
if the remainder of the division is zero, then we know we can cancel out some like factors: a shortcut to seeing if the remainder is zero is to find a value for d that zeros out the bottom (d+3 = 0, when d=-3) and use it on the top to see if the top also zeros out.
3d² + 2d - 29 3(9) + 2(-3) - 29 27 -6 - 29 is not zero, so the bottom is not a factor of the top
ok, now what?
if you are being asked to find the remainder ... 27-6-29 = -8 -8/(d+3) but it is not clear what your end game is spose to be
prolly not
no
So.... what do we do then?
there are over a hundred and sixty-three "things" we can do .... but without knowing what it is that you NEED to do (what is your goal for this), then it would be a bit futile to carry on
IF your intent is to see what factors out, then we determined that at the start .... nothing factors out
if all your teacher is asking you to do is divide .... then id suggest simply dividing out into a quotient and remainder
3d - 7 --------------- d+3 | 3d^2+2d-29 -(3d^2+9d) --------- -7d-29 -(-7d-21) -------- -8
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