PLEASE HELP! How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 grams of calcium metal? Ca (s) + 2HBr (aq) CaBr2 (aq) + H2 (g)
I got 2.00? the answer choices are 1.11 liters 2.22 liters 2.81 liters 22.5 liters
convert 100 g of calcium to moles then use the concentration of the HBr in the molarity equation (don't forget to take the stoichiometric coefficient into account)
so it would be: 100g Ca x 1 mol Ca/ 40.1 g Ca x 2 mol HBr/1 mol Ca x 1 L HCl solution/ 2.5 mol HBr
nope, do one step at a time.. molarity of Hbr = the moles of calciumx2/L you're solving for liters
wait you're actually right
but my answer is 2.00???
but it's 2.25 M not 2.5
oh...wow:/
lol
will you help me with one more?
sure
The density of an unknown gas is found to be 3.44 g/L at standard temperature and pressure (STP). What is the molar mass of this gas?
use the ideal gas law and manipulate it to solve for molar mass
how do I do that..?
algebra and substitution
try it, if you can't do it ill show you
well idk how to start it
ik ideal gas law is Pv=nRT
PV=nRT moles definition: n=m/M PV=mRT/M
3.44g/L x 0.0821L-atm/mole-K x 273K / 1atm = molar mass = 77.1g/mole?
looks right
ok thank you!!
no prob!
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