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Mathematics 19 Online
OpenStudy (goformit100):

If all permutations of the letters of the word AGAIN are arranged in the order as in a dictionary. What is the 49th word?

OpenStudy (goformit100):

@brookester6

OpenStudy (anonymous):

ugg idk..... this one confuses me O.o lol

OpenStudy (goformit100):

@mikaela19900630

OpenStudy (anonymous):

yeah i have no clue

OpenStudy (anonymous):

lol hahah it hurts my brain lol

OpenStudy (goformit100):

I got Starting with letter A, and arranging the other four letters, there are 4! = 24 words. These are the first 24 words. Then starting with G, and arranging A, A, I and N in different ways, there are 4! 12 2!1!1! = words. Next the 37 th word starts with I. There are again 12 words starting with I. This accounts up to the 48 th word. The 49 th word is NAAGI. is it correct ?

OpenStudy (goformit100):

?

OpenStudy (anonymous):

whaaaaaaaat? lolol

OpenStudy (goformit100):

Thank you madam

OpenStudy (anonymous):

Nope. You've got two A's, so there are 24*2 starting with A. It says "all permutations", not "all unique permutations". The 49th permutation is the first one that starts with G: GAAIN!

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