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Check is my answer correct ? A student has to answer 10 questions, choosing atleast 4 from each of Parts A and B. If there are 6 questions in Part A and 7 in Part B, in how many ways can the student choose 10 questions?
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The possibilities are: 4 from Part A and 6 from Part B or 5 from Part A and 5 from Part B or 6 from Part A and 4 from Part B. Therefore, the required number of ways is 6C4×7C6+6C5×7C5+6C6×7C4= 105 + 126 + 35 = 266.
@mikaela19900630
Looks good to me!
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