find the derivative of (x)/(x+5)

Question

anonymous · Answer

$$\left(\frac{f}{g}\right)'=\frac{gf'-fg'}{g^2}$$ with 
$$f(x)=x, f'(x)=1, g(x)=x+5,g'(x)=1$$

anonymous · Answer

i couldn't read your reply

zepdrix · Answer

Does the fancy text not show up?
Are you using Internet Explorer by chance? :o

anonymous · Answer

yes and yes

zepdrix · Answer

Yah Internet Explorer doesn't play nicely with the LaTeX Plugin :(
You should try another browser.

If you don't feel like doing that, I can try to explain it in regular text. c:

anonymous · Answer

yes could you please I used [g(x)*f'(x) - f(x)* g'(x)] / (g(x))^2 --the product rule is that right

zepdrix · Answer

Yes, your quotient rule looks correct.

So we get something like this:

[(x+5)*(x)' - (x)*(x+5)'] / (x+5)^2

Right? Where the primes are the terms we need to differentiate still.

anonymous · Answer

i think i did something wrong i got [(x+5)*(1)-(x)*(1)] / (x+5)^2

espex · Answer

How about if you re-wrote it and used the product rule. $$x(x+5)^{-1}$$

zepdrix · Answer

Yes very good Mizz, see how I had primes on the (x)' and (x+5)' terms?
That let's us know that we need to take the derivative of those terms.

I was simply doing the set up.
The next step would give you what you actually came up with.