Help please! Will become fan..
@thomaster please help me..
@satellite73 help?
which question? or both
yes for both please.
okay the first one is B because colligative properties depends mainly on the quantity of solute molecules present, not necessarily their identity
Alright, then how would you find the next one?
Normal boiling point of water 100˚C Increase of boiling point is 5˚C Boiling point elevation constant is 0.512˚C per mole so the increase = moles * 0.512 Moles = increase / 0.512 the increase is 5 so 5/0.512 = 9.77 mol
alright thank you, can you check my answer?
Vapor pressure is proportional to mole fraction (Raoults Law). 200 g x 1 mol/18 gm = 11.11 moles water 720/745 = 0.966 mol fraction of water after glucose is added. therefor mole fraction glucose=0.034 moles glucose/moles glucose + 11.11 = 0.034 0.966 molesGlucose =0.378 molesGlucose = 0.378/0.966 = 0.39 moles Glucose
Alright thanks. What about this one?
arrhenius and brønsted-lowry
Thank you, what about this one?
Br-
Thanks can you help me on the first question & check my second?
@thomaster you still there?
0-7 = acid 7-14= base
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