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OpenStudy (anonymous):
OpenStudy (anonymous):
@thomaster please help me..
OpenStudy (anonymous):
@satellite73 help?
thomaster (thomaster):
which question? or both
OpenStudy (anonymous):
yes for both please.
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thomaster (thomaster):
okay the first one is B because colligative properties depends mainly on the quantity of solute molecules present, not necessarily their identity
OpenStudy (anonymous):
Alright, then how would you find the next one?
thomaster (thomaster):
Normal boiling point of water 100˚C
Increase of boiling point is 5˚C
Boiling point elevation constant is 0.512˚C per mole
so the increase = moles * 0.512
Moles = increase / 0.512
the increase is 5 so 5/0.512 = 9.77 mol
OpenStudy (anonymous):
alright thank you, can you check my answer?
thomaster (thomaster):
Vapor pressure is proportional to mole fraction (Raoults Law).
200 g x 1 mol/18 gm = 11.11 moles water
720/745 = 0.966 mol fraction of water after glucose is added. therefor mole fraction glucose=0.034
moles glucose/moles glucose + 11.11 = 0.034
0.966 molesGlucose =0.378
molesGlucose = 0.378/0.966 = 0.39 moles Glucose
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OpenStudy (anonymous):
Alright thanks. What about this one?
thomaster (thomaster):
arrhenius and brønsted-lowry
OpenStudy (anonymous):
Thank you, what about this one?
thomaster (thomaster):
Br-
OpenStudy (anonymous):
Thanks can you help me on the first question & check my second?
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