Question

Algebra 1 anybody?????

Answer 1

Yes?

Answer 2

doing quadratics... \[\frac{ x+3 }{ 5^{2}+12x-9 }\]

Answer 3

Try this site http://mathway.com/

Answer 4

\[\Large 5x^{2}+12x-9\]
Factor this. The method i like to use is (it may seem confusing at first, sorry):

start by multiplying the first coefficient (5) by -9, to get -45.

Now you need two numbers that add up to the middle coefficient (12) and multiply to equal -45... (15)(-3) = -45, and 15 - 3 =12

So now write it like this with the 15 and -3, since it was 5x^2 just put 5x in both brackets for now: \[\Large (5x + 15) (5x-3)\] Now, since at the start we multiplied by 5, divide that by 5 (divide the first brackets by 5)... \\[\Large \frac{ (5x + 15) (5x-3) }{ 5} = (x+3)(5x-3)\]

So now... \[\Large \frac{ x+3 }{ 5x^{2}+12x-9 } = \frac{ x+3 }{ (x+3)(5x-3) }\]

Answer 5

sooooooooooo it would be (in the end) \[\frac{ 1 }{ 5x-3 }\] ???????? @agent0smith

Answer 6

SOMEBODY????? oops caps

Answer 7

Can we all back up a tad???

Is the divisor 5^2+2x-9 as written by brookester6, or is it 5x^2+2x-9 as worked by @agent0smith ?

Answer 8

uuuuuuuuuuuuhhhhhhh it's my way cuz i got it from my paper O.o

Answer 9

Drat...even *I* screwed it up!!! Lemme rephrase:

Is the divisor 5^2+12x-9 as written by brookester6, or is it 5x^2+12x-9 as worked by @agent0smith ?

And since we crossed postings, then I guess it's

5^2+12x-9

???

Answer 10

yesh

Answer 11

If that's the case, then aren't we left with a divisor of:

25 +12x - 9

Which is

16+12x ??

Which makes the problem:

(x+3) / (12x + 15)

???

Answer 12

which is 1 over 5x-3 :D) i think i gots it :P lol

Answer 13

DAMMIT!!!! I have got CLUMSYTHUMBS TONIGHT!!!!

I meant:

(x+3) / (12x + 16)

Answer 14

mmhmmm which 3 reduces off of everything and leaves you with (1)/(5x+3) :D) CHEESE!!! ahaha i gots it now thanks a bunches!!

Answer 15

@qweqwe123123123123111 I assumed it was a typo and she left out the x... she said "doing quadratics"

remove the x and it's no longer a quadratic...

Answer 16

hah true dat

Answer 17

@brookester6 wrote:

doing quadratics...
\[\Large \frac{ x+3 }{ 5^{2}+12x-9 }\]

pretty safe to assume there's an x missing in there.

Answer 18

-"she said "doing quadratics...remove the x and it's no longer a quadratic..."

Agreed... :-)

So I asked...

I'm still rather confused. My brain tonight isn't working much better than my thumbs... :(

Answer 19

haah that's okay mine either i had 5 tests and a quiz at school today... boy am i gonna sleep goooooood tonight :D)

Answer 20

@brookester6 \[\Large \frac{ x+3 }{ (x+3)(5x-3) } = \frac{ 1 }{ 5x-3 }\]
Is correct! :)

Answer 21

Yayy!!

:-)

Answer 22

yes dats correct :D) i used the math site