find the indicated term of the given arithmetic sequence a1=115, d=-11, n=12
12th term is -6 I believe?
nice, can you please explain how you got that ? I want to learn it : /
First, An arithmetic sequence is a sequence where each term is found by adding or subtracting the same value from one term to the next. We call this value "common sum" or "common difference"
So pretty much we start from a1, which is 115, then subtract 11 since it's (-11) until we get to n which is 12
Another way to find the number is using this equation, (d) x (n) + (a1 plus or minus (d))
\[-11* 12 + (115-11)\]
For the last part of the equation you need to do the opposite of the given sign, so instead of subtracting 11, you add 11
\[-11*12+(115+11) = -6\]
Do you somewhat get it?
yeah i somewhat get it a little. thank you
Take a1 and add or subtract d depending on the sign, until you reach n. Take 115 and subtract 11 (-11) until the 12th term. 115 would be the firt
1. 115 2. 115-11 =104 3. 104 -11 =93 4. 93-11 = 82 5. 82 -11 =71 6. 71 -11 = 60 7. 60 -11 = 49 8. 49 -11 = 38 9. 38- 11 = 27 10 27 - 11 = 16 11. 16 - 11 =6 ****12th. 5- 11 = -6
Does that help a bit more?
Here is a reference site that can help you out. http://www.basic-mathematics.com/arithmetic-sequence.html
yay ! okay i get it now it took me a minute but i definitely get it now. thank you very much
yw
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