solve each system by elimination 6x+8y=-16 7x+16y=-12 and show work please
If you multiply both sides of the first equation by 2 it will be possible to eliminate the y terms by subtraction. 12x + 16y = -32 7x + 16y = -12 Subtracting the second equation from the first we get 5x = -20 Now you can solve for x.
8y=-6x-16 y=-6/8x-6 or 3/4x - 2 7x+16(3/4x - 2)=12 7x+12x-32=12 19x=44 x=44/19
how would you solve for y
And put numbers and explain it good because this part confuses me
The value of x is -4. We can chose either of the original equations an plug in -4 in place of x. Lets take the first equation, 6x+8y=-16 Putting -4 in place of x we get \[(6\times -4)+8y=-16\] which simplifies to \[-24+8y=-16..............(1)\] Now can you add 24 to both sides of equation (1) to eliminate the -24 term from the left hand side?
Can you explain to me in numbers please
What does the following equation simplify to? -24 + 24 + 8y = -16 + 24
I mean explain how to find y in numbers
I have just given the first stage of finding the value of y. Can you simplify the following equation which has one term in y and the remaining terms are numbers? -24 + 24 + 8y = -16 + 24
can you go through the steps of the processs to find y totally because I am confused
Sure. What is the result of the following: -24 + 24 = ?
-1
am I correct
-24 + 24 = 0 Now can you try the following: -16 + 24 = ?
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