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OpenStudy (anonymous):

Another conics question. (Need tutored, no idea about conics).

OpenStudy (anonymous):

Find the center and radius of a circle that has a diameter with endpoints(-9,-6) and (-1,0).

OpenStudy (anonymous):

hmm here we go bty you can google "conics purplemath" and get real good explanations

OpenStudy (anonymous):

oh i will google that too c:

OpenStudy (anonymous):

ok first you need the center of the circle, which is another way of saying you need to find the midpoint of the line segment

OpenStudy (anonymous):

Isnt it (-9)+1 / (-6)-0?

OpenStudy (anonymous):

you need help with that, or is it clear how to find the midpoint?

OpenStudy (anonymous):

oh no, i think you have the midpoint confused with the "slope" which has nothing to do with this problem

OpenStudy (anonymous):

Oh yeah.. I cant remember the midpoint formula /:

OpenStudy (anonymous):

the midpoint is just the average of each coordinate

OpenStudy (anonymous):

i.e. add up and divide by 2

OpenStudy (anonymous):

add up x and x? or x and y?

OpenStudy (anonymous):

\[\frac{-9-1}{2}=\frac{-10}{2}=-5\] for the \(x\)

OpenStudy (anonymous):

so -5,-3?

OpenStudy (anonymous):

\(x\) and \(x\) for the \(x\) \(y\) and \(y\) for the \(y\) you cannot add or subtract \(x\) and \(y\) they live in different yes

OpenStudy (anonymous):

now we area half way done the general form is \[(x-h)^2+(y-k)^2=r^2\] and you have \(h=-5, k=-3\)

OpenStudy (anonymous):

and the radius is half of the diameter, so (-5,-3) to -1,0) is the radius, so I have to use the distance formula?

OpenStudy (anonymous):

so far we know the equation is going to look like \[(x+5)^2+(y+3)^2=r^2\]

OpenStudy (anonymous):

yes exactly you have to use the distance formula to find \(r\) but before you do, notice that you really need \(r^2\) and not \(r\) so you can use the distance formula without the square root

OpenStudy (anonymous):

in other words compute \[(-1+5)^2+3^2\]

OpenStudy (anonymous):

25

OpenStudy (anonymous):

i hope that is clear, that will give you \(r^2\) which is what you want i get \(4^2+3^2=25\)

OpenStudy (anonymous):

right

OpenStudy (anonymous):

now you are done

OpenStudy (anonymous):

But is the radius 25 units or 5 units?

OpenStudy (anonymous):

\[(x+5)^2+(y+3)^2=25\]

OpenStudy (anonymous):

the radius is \(r\) and since \(r^2=25\) you know \(r=5\)

OpenStudy (anonymous):

Makes perfect sense! Thank you again c:

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

you can send the cookie in the mail

OpenStudy (anonymous):

Haha c:

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