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Mathematics 17 Online
OpenStudy (comm.dan):

I have a question about Adding and Subtracting Radical Expressions. Does it matter what numbers you use when factoring out radicals for Adding and Subtracting Radicals? I will attach an example of a problem.

OpenStudy (comm.dan):

@e.cociuba

OpenStudy (comm.dan):

\[\sqrt{8}+\sqrt{72}=\sqrt{4*2}+\sqrt{36*2}=2\sqrt{2}+6\sqrt{2}=8\sqrt{2}\]

OpenStudy (anonymous):

post the sample i get old

OpenStudy (comm.dan):

That is the sample above, which is what I just posted a few moments ago.

OpenStudy (anonymous):

i dont understand that is right

OpenStudy (comm.dan):

I am asking does it matter what numbers you use to factor out square root 72. Do you have to use 36 X 2 or 9 X 8? @julian25

OpenStudy (anonymous):

You did it correctly.

OpenStudy (comm.dan):

I understand that. But does it matter what numbers you use for factoring out radical expressions?

OpenStudy (anonymous):

9 x 8 is incomplete. After that you would still have to factor the 9 into 3 x 3 and the 8 into 4 x 2. You would still get the same answer either way, but the way that you did it saved you some time by requiring less steps.

OpenStudy (anonymous):

but u will get the same result sqrt(36*2)=sqrt(9*8)= 6*sqrt(2)

OpenStudy (comm.dan):

The 36 X 2 is less work because you have less to factor?

OpenStudy (anonymous):

You were able to see right away that 72 = 36 x 2, and that 36 is a perfect square. That saved you some steps and some time. That's all. If you had factored it differently, and kept factoring until you had factored out all the perfect squares, you would have come up with the same answer.

OpenStudy (comm.dan):

Thank you for the help. @EulersEquation

OpenStudy (anonymous):

Thanks for the props.

OpenStudy (comm.dan):

No problem. @EulersEquation

OpenStudy (comm.dan):

Thank you for helping me, too. @julian25

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