Using Hamilton’s definition of complex numbers, show that complex addition is both associative and commutative. Show that complex multiplication is both associative and commutative.
@terenzreignz
@Hunus
What in the world is Hamilton's definition?.... Stand by... googling...
Can't find it... you better tell me what Hamilton's definition is... All I can find are quaternions...
Or... better call the big guns in :D @satellite73 ?
@terenzreignz ^here are my notes on Hamilton from my History of Math course. Quaternions are mentioned in the notes also.
okay... it seems, and correct me if I'm wrong (and if I'm wrong you should really be able to spot it... assuming you read your notes... I just skimmed through it) The definition for complex numbers is \[\huge \mathbb{C} = \left\{a+bi \left| \quad a,b\in \mathbb{R} \quad , \quad i = \sqrt{-1}\right.\right\}\]
haha well yeah I know that in general from understanding complex numbers @terenzreignz
No need to keep tagging me... just call me TJ, and we'll get along ;) So, let's so associativity, and let \[\LARGE \color{green}{z_1 , z_2, z_3} \in \mathbb{C}\] \[\Large z_1 =a_1+b_1i\]\[\Large z_2 = a_2+b_2i\]\[\Large z_3 = a_3+b_3i\]
*show* associativity
\[\Large (z_1+z_2)+z_3=[(a_1+b_1i)+(a_2+b^2i)]+a_3+b_3i\]
\[\Large = [(a_1+a_2)+(b_1+b_2)i]+a_3+b_3i\]\[\Large =(a_1+a_2+a_3)+(b_1+b_2+b_3)i\] \[\Large = a_1+b_1i + [(a_2+a_3)+(b_2+b_3)i]\]\[\Large = a_1+b_1i+[(a_2+b_2i)+(a_3+b_3i)]\] \[\Large \color{blue}{=z_1+(z_2+z_3)}\] Thus showing associativity
Maybe the commutativity bit, you can do yourself? :)
Okay. Thank you. So for commutativity, do I just show some combination of z1 + z2 + z3 equaling another combination of z1 + z2 + z3?
Just z1 and z2 should be enough. Just need to show that z1 + z2 = z2+ z1 and that's enough :)
Okay. Cool. And for the multiplication .. should they reflect the addition associativity and commutativity?
@terenzreignz
Yes, they should :)
Okay. Thank you
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