The population of a bacteria culture increases at the rate of 3 times the square root of the present population. A. Model the population P = P(t) of the bacteria population with a differential equation. B. Solve the differential equation that models the population P = P(t) of the bacteria population. C. Suppose the population at time t = 0 hours is 1000. Derive an equation for the population P as an explicit function of time t (in hours). Your equation should contain no undetermined constants. D. What’s the population of the bacteria culture at the end of 10 hours? After 100 hours
A. dP/dt = 3SQRT(P) B. dP = 3P^(1/2)dt (1/3)dP*P^(-1/2) = dt t = (2/3)P^(1/2) + c 1.5t = P^(1/2) + c (9/4)t^2 + c = P If we knew the population at a given time we could find out what c is, but we don't. C is just some constant. C. 1000 = (9/4)(0) + c c = 1000 P = (9/4)t^2 + 1000 D. P(100) = 23500 <-- just plug in 100 P(1000) = 225100 <--- plug in 1000 You may want to check that I didn't screw anything up.
thanks
Join our real-time social learning platform and learn together with your friends!