Show that if we define the complex number a + bi as the matrix: (I will attach matrix), with normal matrix addition and multiplication, the definitions of addition and multiplication of complex numbers are correct.
\[\left[\begin{matrix}a & b \\ -b & a\end{matrix}\right]\]
@Hunus @terenzreignz
@amistre64
@AravindG
an hour ago? the notifs must be lagging
show that a adding and multiplying it to a matrix of the same form, produces another matrix of the same form
\[\left[\begin{matrix}a & b \\ -b & a\end{matrix}\right]+\left[\begin{matrix}x & y \\ -y & x\end{matrix}\right]=\left[\begin{matrix}m & n \\ -n & m\end{matrix}\right]\] \[\left[\begin{matrix}a & b \\ -b & a\end{matrix}\right]~\left[\begin{matrix}x & y \\ -y & x\end{matrix}\right]=\left[\begin{matrix}m & n \\ -n & m\end{matrix}\right] \]
Okay. It doesn't matter that you used m and n as the variables in your results when we originally used different variables in our computations? We're just showing that what produced is in the same form as a +bi matrix? @amistre64
And what can I additionally say that clarifies that the definitions of addition and multiplication of complex numbers are correct? @amistre64
producing the same "form" is whats important, yes
well, the addition of complex numbers is again a complex number ... the multilication of complex numbers is again a complex number ... (a+bi) + (x+yi) = (a+x) + (b+y)i (a+bi)(x+yi) = ax + bxi + ayi -by = (ax-by) + (ay+bx)i
so as long as the "form of a complex number" is maintained by the matrix operations ... all is well
Thanks for your help!! I appreciate it. @amistre64
Join our real-time social learning platform and learn together with your friends!