A firecracker shoots up from a hill 160 feet high with an initial speed of 105 feet per second. Using the formula H(t) = −16t2 + vt + s, determine how long it will take the firecracker to hit the ground. 7.5 seconds 7.8 seconds 8.1 seconds 8.3 seconds
@primeralph
okay, do you know calculus?
Madam is it a Physics question or Mathematics Question ?
the whatever will be at the ground twice: when it leaves and when it falls. So, you will have two answers: the larger one is what you want. All you have to do is set the equation = 0, but for v, put160
calculus ? no im in algebra 1 @primeralph and math @goformit100
let me see what you can come up with
you don't need calculus for this problem
@nincompoop in real life, stuff don't work out so easily, except in algebra. That's why I asked.
im confused ... what do i do ?
solve for t
@Denebel she doesn't seem much like a physics person to me............
you're going to get a wrong answer if your v is set to 150
...... i get a decimal
yeah, what's it?
10.342 and -0.96694
@primeralph
i think the reasonable one makes sense in that situation.
The formula is H(t) = -16t^2 + 105t+160 = 0 (because v=105 as stated in your problem). You would also want to disregard any negative numbers because it is not possible to have a negative time
errrr, but them answers ain't in the options
If you solve h(t) = -16t^2 + 105t+160, it matches one of the choices (with rounding)
@Denebel , not really.........
.-.
okay we're wasting a lot of time here...
@Gabylovesyou you'll have to go with 10.34.... even though it isn't in the options
@Gabylovesyou summon me to help :) I don't want to be rude by taking over
@poop, do your thing, time is running out.
You need to use the quadratic formula \[\frac{ -b \pm \sqrt{b ^{2}+4ac} }{ 2a } = \frac{ -105\pm \sqrt{105^{2}-4(-16)(160} }{ 2(-16) }\] Plug this in your calculator. You will get a positive and negative answer. then disregard the negative one
@goformit100: its a dynamics question :)
you know this requires several steps and one other solution is to use the quadratic formula set H(t) to 0 therefore you will have the formula 0 = -16t^2 + 105t+160 since you have a negative as your leading coefficient, you need to first multiply both sides by -1 giving you 0 = 16t^2 - 105t -160 then use the quadratic formula. this also can be solved by completing the square.
oh, twas 105 not 150........ either way the answer ain't in the options
ya I told you from the start that you will get the wrong answer if you set your v to 150
-16 t^2+105 t+160 = 0 Multiply both sides by a term to make the coefficient of t^2 positive. Multiply both sides by -1: 16 t^2-105 t-160 = 0 Using the quadratic formula, solve for t. t = (105±sqrt((-105)^2-4×16 (-160)))/(2×16) = (105±sqrt(11025+10240))/32 = (105±sqrt(21265))/32: Answer: | t = (105+sqrt(21265))/32 or t = (105-sqrt(21265))/32
As @Denebel said , Use quadratic formula ... Remember that the answer will be only da posivtive value
Positive *
but since w're talking about time here and time doesn't go back, unless you want to be Einstein, then obtain the positive value.
whats the answer?
plug into your calculator
do you know how to complete the square yet, @Gabylovesyou
−16t2 + 105t + 160 = 0 @Gabylovesyou please solve, as you solved earlier.
don't forget the caret sign, @primeralph ^ ^ ^ ^ ^ ^ ^ called caret
WUT? is it C?
the answer is in the option when it is rounded off to the first decimal
it has to be in the answers ... .-.
@nincompoop is it C?
no, poop is right, it is among them.
look at this link and tell me if you see http://www.wolframalpha.com/input/?i=0+%3D+-16t%5E2+%2B+105t%2B160 the value very close to the one of the options
@Gabylovesyou what type of calculator do you use?
is it B ?
@primeralph i use wolfram
yeah, B. I mean handheld.
lol finally! ITS B!!!!!!!!!!!!!! right @nincompoop
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