A proton (with charge of 1.6 x 10-19 C) moves perpendicularly through a magnetic field that has a magnitude of 4.5 × 10–3 T. If the proton is moving at 1.0 × 105 m/s, what is the magnitude of the magnetic force on the proton? (7.2 x 10-17 N)

Question

turingtest · Answer

what is the formula for the lorentz force on a moving charge?

turingtest · Answer

the magnetic lorentz force*

anonymous · Answer

Since the proton is moving perpendicular to the field,
$$F=Bqv$$
F=Force on the proton
B=Magnetic flux density (magnitude of the magnetic field)
q=charge on the particle (in this case which is an electron)
v=speed of the particle