Question

Matrices help???

Answer 1

might need a little more to go on ....

Answer 2

\[\left[\begin{matrix}15 & 8 \\ 4x & 0\end{matrix}\right]-\left[\begin{matrix}2 & 5 \\ x & 3y+6\end{matrix}\right]=\left[\begin{matrix}13 & 3 \\ 12 & 4y+8\end{matrix}\right]\]

Answer 3

@amistre64

Answer 4

adding and subtractg matrixes is a by equivalent parts operation

Answer 5

I have to find the values of x and y

Answer 6

\[\left[\begin{matrix}15 & 8 \\ 4x & 0\end{matrix}\right]-\left[\begin{matrix}2 & 5 \\ x & 3y+6\end{matrix}\right]=\left[\begin{matrix}13 & 3 \\ 12 & 4y+8\end{matrix}\right]\]

\[\left[\begin{matrix}15-2 & 8-5 \\ 4x-x & 0-(3y+6)\end{matrix}\right]=\left[\begin{matrix}13 & 3 \\ 12 & 4y+8\end{matrix}\right]\]

\[\left[\begin{matrix}15-2=13 & 8-5=3\\ \\ 4x-x=12 & -(3y+6)=4y+8\end{matrix}\right]\]

Answer 7

I'm lost...

Answer 8

then youll have to tell me where you are lost at, i made it as explicit as possible

Answer 9

I have to find the values of x and y..

Answer 10

then solve them from the last matrix setup .... after all, they are just basic linear equations

Answer 11

is it x=-4 and y=2?

Answer 12

@amistre64

Answer 13

4x-x=12
3x = 12
x = 4

-(3y+6) = 4y+8
-3y-6 = 4y+8
-14 = 7y
y = -2

Answer 14

you were close :)

Answer 15

Ahh mixed up those negatives :b Thank you!!

Answer 16

good luck ;)