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OpenStudy (anonymous):
Find the convolution of
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OpenStudy (anonymous):
fa=1 0<=x<=a, 0 otherwise
fb=1 0<=x<=b, 0 otherwise
fa*fb?
OpenStudy (amistre64):
an integral that expresses the amount of overlap one function is shifted over the other
OpenStudy (anonymous):
I understand that, but i dont know how to do the integral
is fa*fb=\[\int\limits_{0}^{t}1*1*dt=t?\]
OpenStudy (amistre64):
i see something about \(\large \tau\)
OpenStudy (amistre64):
is that f(a) = 1 on the interval [0,a]
and f(b) = 1 on the interval [0,b]
??
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OpenStudy (anonymous):
\[\int\limits_{0}^{t}f(u)g(t-u)du\]
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
u is fine as well
OpenStudy (amistre64):
do we assume a < b ?
OpenStudy (amistre64):
just a gut feeling, but im curious if this amounts to F(b) - F(a)
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OpenStudy (anonymous):
i dont think so
\[\int\limits_{0}^{t}f _{a}(u)f_{b}(u-t)du=\int\limits_{0}^{\min(a,b)}1*1*du=\min(a,b)?\]
OpenStudy (amistre64):
that is correct, the amount of overlap of the functions, they are y = 1 after all; is the minimum of a and b
OpenStudy (amistre64):
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