sin x (csc x-sin x) = cos^2 x
Do you know the trigonometric functions?
i dont understand this at all. i cant do math
Ok Ill show you some trigonometric functions to make this breeze.
okay thank you
give me one sec to gather
thats fine
http://www.sosmath.com/trig/Trig5/trig5/trig5.html check out this site, it will give you all the info you need.
You question asks you to solve for sin x (csc x-sin x) = cos^2 x Now lets work out all that is in parenthesis
If you follow the website I gave you, you would know that cscx= \[\frac{ 1 }{ sinx }\] and sinx in return is sinx= \[\frac{ 1 }{cscx }\] So Now we have \[\frac{ sinx }{ 1 }(\frac{ 1 }{ sinx}-\frac{ 1 }{ cscx })=\cos^2x\]
I made an error. instead of \[\frac{ sinx }{ 1 }\] Its 1/cscx Now distribute that to everything in parenthesis. You get sinx^2-1=cosx^2 subtract cosx^2 on both sides. Then add 1 on both sides. Your final answer is \[sinx^2-cosx^2=1\] which is an identity.
you are a life saver. thank you!
No Problem!
Join our real-time social learning platform and learn together with your friends!