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Mathematics 15 Online
OpenStudy (deadshot):

How do I find the 15th term of the geometric sequence 52, 39, 29.25 ...?

OpenStudy (blurbendy):

is that supposed to be, 29, 25? or is it 29.25?

OpenStudy (deadshot):

it's 29.25

OpenStudy (kropot72):

The common ratio is 39/52 = 0.75 The formula for the n^th term of a geometric series is \[n ^{th}\ term=ar ^{n-1}\] where a is the first term and r is the common ratio. The 15th term is \[52\times (0.75)^{14}=you\ can\ calculate\]

OpenStudy (deadshot):

So the 15th term would be \[a _{15} ≈ 0.93\]

OpenStudy (deadshot):

right?

OpenStudy (kropot72):

You are correct, if the rounding is as specified in the question.

OpenStudy (deadshot):

Okay, thanks for the help!

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