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Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the original logarithmic expressions. Give the exact answer. log6x2 = log6(5x + 36)
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A. (3/2) B. {9} C. Ø D. {9, -4}
Your username/picture is awesome. *_*
lol thanks ;-P
You're welcome. (:
log 6 + logx^2 = log6 + log(5x+36) logx^2 = log(5x+36) taking antilogs, x^2 = 5x + 36 What do you do after this
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\[x^2 -5x-36=0\\x^2+4x-9x-36\\ x(x+4)-9(x+4)\\(x-9)(x+4)\\ x=9 \ \ \ x=-4\]
thank you ;-) @perurabo
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