How would you prepare 150.0 mL of a 0.200 M aqueous solution of potassium chloride from a
0.500 M aqueous solution of potassium chloride?

A. Add 60.0 mL of water to the 0.500 M solution.

B. Take 60.0 mL of the 0.500 M solution and add enough water to complete to 150.0 mL of solution.
C. Add 90.0 mL of water to the 0.500 M solution.

D. Take 90.0 mL of the 0.500 M solution and add enough water to complete to 150.0 mL of solution.

Question

How would you prepare 150.0 mL of a 0.200 M aqueous solution of potassium chloride from a
        0.500 M aqueous solution of potassium chloride?

A.	Add 60.0 mL of water to the 0.500 M solution.

B.	Take 60.0 mL of the 0.500 M solution and add enough water to complete to 150.0 mL of solution.
C.	Add 90.0 mL of water to the 0.500 M solution.

D.	Take 90.0 mL of the 0.500 M solution and add enough water to complete to 150.0 mL of solution.

aaronq · Answer

Determine volume of initial solution needed using:
$$C _{1}V _{1}=C _{2}V _{2}$$

then top up to whatever the total volume is to be.

anonymous · Answer

what does C stand for?