Tony plotted points P, Q, and R to represent the vertices of a triangle as shown in the figure below.
What should Tony do to make triangle PQR an acute scalene triangle? Answer Choices: Move Q to the right of segment XY beyond the arc. Move P to the point of intersection of segment XY and the arc. Move R to the point of intersection of segment XY and segment LM. Move P to the right of segment XY beyond the arc.
@tible19 @qweqwe123123123123111 do you know this one? I dont even have a guess
well it wouldnt be a because that would make it obtuse...
@tible19 i barely remember this
wait i mean that would make it a right triangle...
grr wait b would make it a right triangle
@tible19 so its definitely not A or B?O.o
right...
This is the WEIRDEST damned question I think I've ever seen on here. Much as I dislike just handing out answers, I'm just gonna do it here because it's so bizarre. Move P to the right of segment XY beyond the arc. That makes Q an acute angle with no possibility of any legs being equal length (which is the definition of a scalene)
lol i was about to say that
:-)
@tible19 @qweqwe123123123123111 ohh okay thank you guys so muchhh(:!
NP!! And thanks!! :-)
glad to be of service :3
i have another question that im stuck between two answers
ok
do i put it here or another post?
either way i don't mind
Look at the triangle XYZ with O as its circumcenter. Which line segment will pass through point O in the triangle XYZ? Answer Choices: The line segment from angle Z perpendicular to side XY. The line segment from angle X that is perpendicular to side ZY. The line segment bisecting angle XZY. The line segment which is the perpendicular bisector of side ZY.
im thinking its D?
or B?
ok...
@tible19 ok im right? or ok you're thinking lol?
the second .-.
@tible19 ohh okay lol
lol uh yeah i think it is B... but you might wanna ask qweqwe first
@tible19 okay thanks. @qweqwe123123123123111 do you agree its B?
i dont know what to put:/
Nope, it's not B The circumcenter of a triangle is that point through which all PERPINDICULAR BISECTORS of every side pass through. They only bisect their opposite angle on a isosceles or equilateral triangle.
@qweqwe123123123123111 so is it D?
IOW, draw a line at a right angle to any side and put it at the center of that side, and all 3 lines will pass through a single point called the "circumcenter"
Yup. D. :-)
@qweqwe123123123123111 yayyyyy lol
The red dot in the middle of this triangle is its circumcenter:
@qweqwe123123123123111 so the point O is the circumcenter of the triangle in the question?
@qweqwe123123123123111 @tible19 i tagged you in another question that i need help
ok
sorry i was finishing a science test
@tible19 its okay take your time
ok what question did you need help on?
@tible19 i tagged you in it again
Yes!! Very good!! :-) BTW, there's another kind of triangle center called a "centroid" that is the "center of gravity" so to speak of a triangle. In that kind, drawing lines from the centers of the side through the verteces of their opposite angles will also pass through a single point called its "centroid"
@qweqwe123123123123111 ohh yes i remember studying centroids (:
I can't find any other tags but here. Where's your "other question"?
@ganeshie8
First question....
Move P to the right of segment XY beyond the arc.
that gives u acute scalene
THanks!
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