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How do I find the 16th term of a geometric sequence where a{subscript(1)} = 4 and a{subscript(8)} = -8,748.
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\[a _{1}=4\]and\[a _{8}=-8,748\]
since you know a1, and the general formula for a geometric sequence is:\[a_n=a_1~r^{n-1}\] you can determine r readily
\[4\times r ^{7}= -8748\]
\[\sqrt[7]{-2187} = -3 = r \]
\[ar ^{15}= 4 \times (-3)^{15}= -57395628\]
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