Question

Supppose f and g are differentibale everywhere with f(2)=4, f'(2)=3 f'(-2)=6 g(2)=-2 and (2)=5. Find H'(2) if: H(x)=f(x)g(x)

Answer 1

Hint:

By the product rule

If H(x)=f(x)g(x)

then

H'(x)=f'(x)g(x) + f(x)g'(x)

Answer 2

Thank You Very Much. This was so helpful and I got it figured out. Thanks Again.

Answer 3

you're welcome