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Mathematics 8 Online
OpenStudy (anonymous):

PLESE HELP WILL GIVE MEDALS Use the graph of f(x) = log x to obtain the graph of g(x) = log x + 5.

OpenStudy (anonymous):

OpenStudy (campbell_st):

do you know what the graph of y = log(x) looks like..?

OpenStudy (anonymous):

YES

OpenStudy (campbell_st):

ok.... then you just add 5 to it... so using a simple table of values may give you an idea x: 1/100 1/10 1 10 100 --------------------------------------- f(x) 3 4 5 6 7

OpenStudy (campbell_st):

the x intercept is at 10^-5 or 1/100000

OpenStudy (campbell_st):

so the graph of log(x) have moved up 5 units...

OpenStudy (anonymous):

MY OP2 ATTACH PICTURE

OpenStudy (campbell_st):

thats correct

OpenStudy (anonymous):

THANKS @campbell_st ;-)

OpenStudy (campbell_st):

but there is 1 issue you are looking at \[y = \log(x) + 5\] and not \[y = \log(x + 5)\] as they are different graphs...

OpenStudy (campbell_st):

if you are looking at y = log(x + 5) there its not option 2... its option 4

OpenStudy (campbell_st):

ok... good luck

OpenStudy (anonymous):

IM ALITTLE CONFUSED NOW. WHICH OPTION IS g(x) = log x + 5.

OpenStudy (campbell_st):

g(x) = log(x) + 5 is option 2

OpenStudy (anonymous):

OK DOES IT MATTER IF IT g(x) = log (x) + 5. BECAUSE IN MY WORK ITS JUST g(x) = log x + 5. NO ()

OpenStudy (anonymous):

f(x)=logx \[f \left( 0 \right)=\log 0=-\infty ,f(1)=0,f \left( \infty \right)=\infty \]|dw:1367957889657:dw| \[f \left( x \right)=\log x+5, f(0)=-\infty+5=-\infty,f \left( 1 \right)=\log 1 +5=0+5=5,f \left( \infty \right) =\infty+5=\]|dw:1367958514925:dw|

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