A soccer player bumps the ball with her head. She is standing so that her head is 5 feet above the ground when she bumps it and the ball goes straight up with an initial velocity of 12ft/s. at what point in time is the ball the highest in the air? Vertical motion formula: -16t+vt+s (where v is initial velocity and s is initial height.

Question

anonymous · Answer

Help

jdoe0001 · Answer

isn't your equation meant to be $s= -16^2+v_ot+s_o$?

anonymous · Answer

No

jdoe0001 · Answer

ahemm, the vertical motion formulat is $s= -16^2+v_ot+s_o$, thus

anonymous · Answer

Well maybe that's another way of writing it but in my class we do it this way

jdoe0001 · Answer

right, are you doing parabolas?

jdoe0001 · Answer

cuz that's what that would be using the vertical motion formula

mathstudent55 · Answer

@Meggie1999
You have -16t+vt+s
I think you are missing the exponent in the -16t term. I think it should be
-16t^2 + vt + s

jdoe0001 · Answer

anyhow, check the picture, that'd be the 'vertical motion formula', using the values provided, is a parabola function, and thus your HIGHEST point, will be where the VERTEX is at, you just need to use that standard form in the picture :)

jdoe0001 · Answer

the "a" value will be negative, since the parabola is going downward