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Solve. \[\frac{ 8 }{ x } + \frac{ 15 }{ x^{2} } = -1\] Answer choices are A. x=5, -3 B. x=-5, -3 C. x=-5, 3 D. x=5, 3
Using x^2 as a common denominator for the left hand side \[\frac{8x+15}{x ^{2}}=-1\] then cross-multiplying \[-x ^{2}=8x+15\] and rearranging \[x ^{2}+8x+15=0\] Now just factorise the quadratic to find the roots.
But how do I get rid of the x^2? @kropot72
Answer: (x - 5)(x - 3)
B. x=-5, -3
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