Question

lim x→0 sinx^2/ x^2

Answer 1

1

Answer 2

could u use L hopital?

Answer 3

make variable substitution: \(x^2=t\)
then: as x->0 x^2->0. ASo it's ok.

Answer 4

i still don't understand

Answer 5

yes it is like u say @myko

Answer 6

well it is no clear if it is sinx^2 or (sinx)^2

Answer 7

You can also use the fact that for \(x\) near 0, \(\sin(x^2)\approx x^2\), so you have
\[\lim_{x\to0}\frac{x^2}{x^2}=1\]

Answer 8

\[\frac{ \sin x^{2} }{ x^{2} } \]
i think this is the problem

Answer 9

@iHeartYou i will be great if u write the problem in that way

Answer 10

@julian25 that's the problem. i just don't know how to write like that

Answer 11

ok it is like myko says
if t =x^2
u get
\[\frac{ \sin(x) }{ x }\]
and u already now the limit of than when x->0

Answer 12

sorry \[\frac{ \sin(t) }{ t }\]

Answer 13

where does the t come from

Answer 14

it is the same because when x^2 ->0, t->0 too