Question

let v1=(3,5) and v2=(-4,7).

Compute |v1| and |v2|.

Answer 1

if v = <x,y> then

|v| = sqrt( x^2 + y^2 )

Answer 2

So then we would plug in the numbers for each one to get it to equal the |v1| and |v2|

Answer 3

In the case of v1 = <3, 5>, we get


|v| = sqrt( x^2 + y^2 )


|v1| = sqrt( 3^2 + 5^2 )


|v1| = sqrt( 9 + 25 )


|v1| = sqrt( 34 )

Answer 4

I'll let you do |v2|

Answer 5

correct

Answer 6

so then the |v2| will equal sqrt65

Answer 7

yep, you got it

Answer 8

How would we then lable the v1 and v2 coordinates and the unit vectors on a graph? I have the unit vectors but not forsure how to put on a graph

Answer 9

to graph v1, you just plot the point (3, 5) and draw an arrow from (0,0) to (3,5)

the tip of the arrow is pointing to (3,5)

Answer 10

do the same for v2

Answer 11

Ok but how would we graph the unit vectors of (3/sqrt34) and (5/sqrt34)

Answer 12

well you can convert that to decimal form to get a better idea of what it looks like

Answer 13

Ok, but the x would be the first part and the y would be the 5///

Answer 14

yes,

x = 3/sqrt(34) = 3/5.83095 = 0.5144959

Answer 15

I got 0.51 and 0.86

Answer 16

y = 5/sqrt(34) = 5/5.83095 = 0.8574932

Answer 17

close enough, the unit vector pointing in the same direction as v1 is < 0.51, 0.86 >

Answer 18

The 0.51=x
the 0.86=y?

Answer 19

yes

Answer 20

Alright thank yoU!

Answer 21

If i could give youanother metal i would!!

Answer 22

you're welcome and it's fine