Question

Please Help!!! find the center (h,k) and radius r of circle with given equation.
x^2+y^2+10x-16y=-73

Answer 1

c(-5,-8) and your radius is 4.

Answer 2

hmmm i don't think that is right

Answer 3

\[x^2+y^2+10x-16y=-73\]
\[x^2+10x+y^2-16y=-73\] now you have to complete the square
\[(x+5)^2+(y-8)^2=-73+5^2+8^2=16\] so center is
\((-5,8)\) and radius is \(4\)

Answer 4

\[x ^{2} + 10x + y ^{2} - 16y = -73\]

Now complete the squares for x and y

\[x ^{2} + 10x + 25 + y ^{2} -16y +64 = -73+25+64\]
\[(x + 5)^{^{2}} + (y-8)^{2} = 16\]

Now this is of the form

\[(x-h)^{2} + (y-k)^{2} = r ^{2}\]

\[(h,k) \space is \space the \space center \]

\[r \space is \space the \space radius\]

Center is (-5,8) and radius is 4

Answer 5

thank you guys so much im not sure who to give the best response to :( you both helped alot.