Question

line l has equation y=-1/2x+4, and point P has coordinates (3,5). a. Find the equation of line m that passes through P and is perpendicular to l

Answer 1

\[ \begin{array}l\color{red}{\text{W}}\color{red}{\text{E}}\color{red}{\text{L}}\color{red}{\text{C}}\color{red}{\text{O}}\color{red}{\text{M}}\color{red}{\text{E}}\color{red}{\text{ }}\color{red}{\text{T}}\color{red}{\text{O}}\color{red}{\text{ }}\color{red}{\text{O}}\color{red}{\text{P}}\color{red}{\text{E}}\color{red}{\text{N}}\color{red}{\text{S}}\color{red}{\text{T}}\color{red}{\text{U}}\color{red}{\text{D}}\color{red}{\text{Y}}\color{red}{\text{}}\end{array} \]

Alright, so the equation can be given by plugging in the (3, 5) coordinates to the slope-intercept formula

y = mx + b
y = 3x + 5

Answer 2

that is not correct Compassionate

Answer 3

Oh - am I wrong? I must not have understood what he was asking.

Answer 4

LIne I is\[y = -\frac{ 1 }{ 2} \times x + 4\]

Slope is -1/2 = \[m _{1}\]

A line that is perpendicular to I will have a slope \[-\frac{ 1 }{ m _{1} }\]

So slope of line m is 2

Answer 5

Now the equation of the line in Slope intercept form can be written as

\[y = 2x + b\]

now to find b you are given a point which says when x = 3 ; y = 5. Plug these values in the equation.

\[5 = 2(3) + b\]

b = -1

Now the equation of the line m which is perpendicular to Line I is

\[y = 2x - 1\]