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Mathematics 14 Online
OpenStudy (anonymous):

Using disks or washers, find the volume of the solid obtained by rotating the region bounded by the curves y=x y=0 x=2 and x=4 about the line x=1

OpenStudy (anonymous):

OK, this can be expressed as an integral. Give me a moment.

OpenStudy (anonymous):

That's not it. It's being rotated around x=1.

OpenStudy (anonymous):

|dw:1367984323351:dw|

OpenStudy (anonymous):

Ahh, didn't see that, thanks

OpenStudy (anonymous):

Here goes...

OpenStudy (anonymous):

I have that graph, but i just dont know what else or how to set it up correctly :(

OpenStudy (anonymous):

\[V=\pi r^{2}\]

OpenStudy (anonymous):

Now we need to get a function for r and integrate it.

OpenStudy (anonymous):

so its in terms of 0 to 4. ?

OpenStudy (anonymous):

\[r=x-1\]

OpenStudy (anonymous):

I'd do in terms of y I think: \[pi*\int\limits_{0}^{4}y^2-2^2\] Right? Probably messed something up there And yes, if you do in terms of y you'd go from 0 to 4. Fixed something in the integral. It's too late, lol.

OpenStudy (anonymous):

i get confused when to use x or y in the shell method? So although it asks for disks/washers, i can use Shells?

OpenStudy (anonymous):

That equation above there is washers, pi*r^2 - pi*r^2, outer disk minus inner disk, that's a washer.

OpenStudy (anonymous):

still doesn't help, i know that but what is the outer and what is the inner?

zepdrix (zepdrix):

|dw:1367984820476:dw|Lemme see if I can draw this for you, maybe we can make some sense of it.

zepdrix (zepdrix):

|dw:1367984904661:dw|So we'll make a small slice horizontally like this, and spin it around x=1.

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