Question

(9-4i)-(9-4i)=91-72i???

Answer 1

81-72i is the answer??

Answer 2

The answer would be zero

Answer 3

zero.....? that is definitly not what i got

Answer 4

You're basically subtracting one thing with the same thing due to the parenthesis
so it's 0

Answer 5

You're subtracting (9-4i) from itself

Answer 6

the original question was (9-4i)^2

Answer 7

Oh

Answer 8

ohh in that case you would foil

Answer 9

i dont think the answer is zero

Answer 10

so i got 81-72i just dont think my answer is right but i know it's not 0

Answer 11

\[(9-4i)^2=(9-4i)(9-4i)=9*9-4i*9-4i*9+4i*4i\]

Answer 12

yes hunus that was my steps as well

Answer 13

The question your posted says (9-4i)-(9-4i)

Answer 14

sorry i was trying to show the first step i did

Answer 15

It's fine :)

first
\[(9−4i)^2=(9−4i)(9−4i)=9∗9−4i∗9−4i∗9+4i∗4i\]
then
\[9∗9−4i∗9−4i∗9+4i∗4i = 81 -36i - 36i +16i^2 = 81 - 72i -16=65 - 72i\]

Answer 16

i definitely found my mistake thank you so much.

Answer 17

i gave you a medal

Answer 18

Yup :)

Answer 19

thanks :D