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permutations : how many ways can 5 people (A-E) sit in a row if A must be to the left of B not not necessarily right next to each other? how many ways if A and B CANNOT sit next to eachother?
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Are there any options? I got the first one as 24 ways. And the second one as 72 ways. I could be wrong. :-|
no its not a multiple choice
can u justify your answers?
Err, the first one : _ _ _ _ B because A HAS to be before B. So, it can be done in 4 * 3 * 2 * 1 ways. The second one, All the number of ways that they can be arranged so that they aren't together is 12 ways. And the other letters in 3 * 2 ways. Therefore, 12 * 3 * 2 = 72. :-| That's how I did.
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